A type that represents a position in the collection.
Valid indices consist of the position of every element and a
"past the end" position that's not valid for use as a subscript
argument.
Returns a value that is offset the specified distance from this value.
Use the `advanced(by:)` method in generic code to offset a value by a
specified distance. If you're working directly with numeric values, use
the addition operator (`+`) instead of this method.
func addOne<T: Strideable>(to x: T) -> T
where T.Stride: ExpressibleByIntegerLiteral
{
return x.advanced(by: 1)
}
let x = addOne(to: 5)
// x == 6
let y = addOne(to: 3.5)
// y = 4.5
If this type's `Stride` type conforms to `BinaryInteger`, then for a
value `x`, a distance `n`, and a value `y = x.advanced(by: n)`,
`x.distance(to: y) == n`. Using this method with types that have a
noninteger `Stride` may result in an approximation. If the result of
advancing by `n` is not representable as a value of this type, then a
runtime error may occur.
- Parameter n: The distance to advance this value.
- Returns: A value that is offset from this value by `n`.
- Complexity: O(1)
method · iOS 27.0+
distance
TypeScript
distance(other: Transcript_HistoryView_Index): number
Swift declaration
func distance(to other: Transcript.HistoryView.Index) -> Int
Returns the distance from this value to the given value, expressed as a
stride.
If this type's `Stride` type conforms to `BinaryInteger`, then for two
values `x` and `y`, and a distance `n = x.distance(to: y)`,
`x.advanced(by: n) == y`. Using this method with types that have a
noninteger `Stride` may result in an approximation.
- Parameter other: The value to calculate the distance to.
- Returns: The distance from this value to `other`.
- Complexity: O(1)
